ESEARCH OF WATER RESISTANCE OF COAT FABRIC

ABSTRACT

In the article, the water resistance (water permeability) property of suit fabric with 100% cotton yarn, 50% polyester and 50% cotton fibers was studied. Average value of research results, mean square deviation, coefficient of variation, The quality of the results was analyzed according to the A.N. Kolmogorov criterion.

The effect of thermal factors leads to aging and changes in the structure of the adhesive material - polymer sewing thread, glue and adhesive bonding, polymer base material and solder bonding. Vse eto takje privodit k snijeniyu prochnosti soedineniy detaley izdeliya.

 To compare its results, the results of the water resistance of the 1.5-layer fabric were checked using the Shapiro Wilkie criterion, and n = 10, W 0.05 = 0.842. W = 0.964 > W 0.05.= 0.842 it can be concluded that the obtained results correspond to the normal distribution law. able 1ing order, V, mm water.

АННОТАЦИЯ

В статье было изучено свойство водостойкости (водопроницаемости) ткани для пальто, состоящей из 100% хлопчатобумажной пряжи, 50% полиэстера и 50% хлопчатобумажных волокон. Среднее значение результатов исследования, среднеквадратичное отклонение, коэффициент вариации, качество результатов анализировались по критерию А.Н. Колмогорова.

Воздействие термических факторов приводит к старению и изменению структуры клеевого материала - полимерной швейной нити, клея и адгезионного соединения, полимерной основы и паяного соединения. Все это так же приводит к уменьшению прочности соединений деталей изделия.

Чтобы сравнить его результаты, результаты водостойкости 1,5-слойной ткани были проверены с использованием критерия Шапиро Уилки, и n = 10, W 0,05 = 0,842. W = 0,964 > W 0,05.= 0,842 можно сделать вывод, что полученные результаты соответствуют нормальному закону распределения.

Keywords: cotton, polyester, coat fabric, water resistance, criterion, standard deviation, coefficient of variation, criterion, theoretical probabilities.

Ключевые слова: хлопок, полиэстер, ткани для пальто, водонепроницаемость, критерий, стандартное отклонение, коэффициент вариации, критерий, теоретические вероятности.

This is the first most important PC of raincoat fabrics; its weight is the greatest and amounts to B = 2.5. Tests were carried out in accordance with GOST 3816 “Textile fabrics. Methods for determining hygroscopic and water-repellent properties" using a penetrometer device [1, 2].

Water resistance is determined by the height of the water column in mm, corresponding to the moment the first three drops of water appear in different places on the inner surface of the sample. To carry out the test, at least five round samples with a diameter of at least 160 mm or a square sample with a size of 160x160 mm are cut from a spot sample so that they do not contain the same groups of warp threads or loop stitches and weft threads or loop rows, as well as local vices.

To assess the compliance of the distribution of test results with the theoretical law, the standard number of tests is not enough, so an increased number of measurements was carried out, amounting to ten. Let us consider the methodology for analyzing and selecting a statistical model of the water resistance of the fabric under study[3, 4].

The following results for determining water resistance were obtained: 865; 856; 859;849; 864; 865;859; 857; 869;861 mm water column. Based on these primary data, the following were found: average value B ̅ = 860.4 mm water column. Standard deviation found by the formula:

Where Х_i are the results of determining water resistance;

-  -sample average

 = V((865 - 860,4 + 856 - 860,4 + 859 - 860,4 + 849 - 860,4 + 864 - 860,4 + 865 - 860,4+ 859-860,4 + 857-860,4 + 869-860,4 +86 1 - 860,4)²/10) = 5,72 ммwat.kup., coefficient of variation found by the formula:

Since the normal distribution is most widespread, it is advisable to start checking the consistency of the results of determining the water resistance of the tissues under study with it. In addition, the water resistance of fabrics depends on a large number of different factors, which corresponds to the probabilistic-statistical model of the normal law. To construct a leveling line, it is enough to calculate two points using the formula:

where Xi is the value of the random variable;

-average value;

 - standard deviation.

In this example, these are the extreme points of the sample. For the data under consideration we have.

A straight line is drawn along the found points. If the experimental points are located near the straight line, then the distribution under study corresponds to the selected theoretical one[5, 6].

Table 1 shows an example of the necessary calculations for plotting the water resistance values of raincoat fabric 1 on normal law probability paper.

Table 1.

Example of the necessary calculations for plotting the water resistance values of raincoat fabric 1 on normal law probability paper

Knowing the Xi results and the corresponding Up', the corresponding results are plotted on the probability paper and a straight line is drawn through the obtained points. If the experimental points are grouped quite well around a straight line in the middle zone of the graph, i.e. If the points lie on a straight line or are at a very small distance from it, then we can assume that the experimental distribution does not contradict the theoretical one.

In Figure 1 shows the probability paper for the normal law and the location on it of the distribution points of the water resistance test results of raincoat fabric 1, as well as the leveling straight line. It can be seen from the graph that the points are well grouped around a straight line, so it is possible to use the normal distribution law to interpret the results of testing the water resistance of fabrics[7]. Let us check the compliance of the results obtained with the water resistance of raincoat fabric 1 according to A.N. Kolmogorov, which is based on the maximum value of the discrepancy Dn between the accumulated frequencies of the empirical and theoretical distributions:

where n- is the number of tests.

For this purpose in table. 2 we write down the test results in ascending order. Determine the empirical frequencies Wi, as well as the accumulated frequencies Wi’. Values of accumulated theoretical frequencies Wi’ for normaldistributionsare determined by the value.

Next, the absolute values of the differences (Wi’- Wi) are calculated for each line and the maximum of them is designated Dn

Table 2.

The test results

Probability of a 3rd drop of water appearing

Water resistance mm waterstan

Figure 1. Results of determining water resistance for raincoat fabric based on the probability of the normal law

For the results of determining the water resistance of raincoat fabric, Dn = 0.08, therefore, according to formula (3.9) = 0.253. According to the table of probability values, P( ) = 0.999 > 0.05 = q. From the calculations it follows that the hypothesis that the test results correspond to the normal distribution law is not rejected [8].

As a rule, the Kolmogorov test is used for continuous distributions with a sufficiently large sample size, so for this calculation example it is more preferable to use the Shapiro Wilkie test

To calculate the Shapiro-Wilkie criterion (Table 3.4), the results of primary measurements are ranked in ascending order and the values of the ordinal index i are written in column 1, and the corresponding ranked values in column 2. In column 3, write the values of X2i, and in column 4, the values of the ordinal index j = 1,2, ..., e, starting from the last line in the reverse order compared to writing the values of index i. In this case, e = 0.5 • (n- 1), if n is an odd number. In our case, with n = 5 • e = 0.5 • (5-1) = 2. In column 5, the values of coefficient A corresponding to index j, which are determined for a given number of measurements (n = 10).The calculated differences Xn-j+1-Xj are inserted into column 6. In column 7, enter the values of the products of values in columns 5 and 6. The data in columns 2, 3 and 7 are summed up and written in the last line (Table 3).

Cording to the data indicated in table. 3.3, calculate the values ( 2 and b2 using the formulas:

²= ( 8 4 9 ² + 856 ²+ 857² + 859 ² + 859² + 861 ² + 864² + 865² + 865² ++869 ² ) -(849 + 856 + 857 + 859 + 859 + 861 + 864 + 865 + 865 + 8б9)²/10 = 294,40;

=0,0399 (869-849) +0,1224 (865-856) +0,214 (865-857) +0,3291(864-859)+ +0,5739(861-859) = 16,84;

The Shapiro-Wilkie criterion is calculated using the formula:

The obtained W values are compared with the table value of W_0.05. If W <W_0.05, then the probability that the sample under study from the general population has a normal distribution does not exceed 0.05, therefore, the hypothesis isrejected. In table 3 shows an example of calculating the criterion W for a primary population that has a normal distribution and does not exceed 0.05, therefore, the hypothesis is rejected[9, 10].

Table 3 shows an example of calculating the criterion for the primary results of determining the water resistance of raincoat fabric.

Table 3.

Example of calculating the criterion for the primary results of determining the water resistance of raincoat fabric

As a result of the calculations, the following values were obtained: =249.40; b 2 =283.74; W=0.964.

With the number of tests n = 10, W 0.05 = 0.842. Since W = 0.964 > W 0.05.= 0.842, we can conclude that the results correspond to the normal distribution law.

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