Associate Professor of the Department of Mathematics, Andijan State University, Republic of Uzbekistan, Andijan
THE PROBLEM OF CAPTURING ONE FUGITIVE IN A GROUP DIFFERENTIAL GAME
ABSTRACT
In this paper, using the example of L. S. Pontryagin, we study the issue of the pursuit of one fugitive by several pursuers. All players have the same dynamic options. Such issues have been studied in the literature. In this paper, the interception problem is solved under the assumption that the solution of the Cauchy problem for a system-compatible homogeneous system is recurrent.
АННОТАЦИЯ
В данной работе на примере Л. С. Понтрягина исследуется вопрос о преследовании одного беглеца несколькими преследователями. Все игроки имеют одинаковые динамические возможности. Такие вопросы изучались в литературе. В данной работе задача перехвата решается в предположении рекуррентности решения задачи Коши для системно-совместимой однородной системы.
Keywords: differential game, group pursuit, capture problem, Pontryagin's example.
Ключевые слова: дифференциальная игра, групповое преследование, задача поимки, пример Понтрягина.
we consider a differential game with players in a space where are the pursuers and E is the fugitive. The law of motion of each hunter for Pi
The law of motion of every hunter Pi
has a look. E - evasive law of motion
has a look. Here and then [t_0,∞) are continuous in the interval - is a compact set with a rigid convex smooth boundary, a part of the space . .
given initial condition [1], that's all .
Denote the game under consideration by .
(1) – (4) instead of these systems
System
look at the initial state. let it be.
is the history of the control of the evader at time .
reported to the collection.
1- definition. If back to original state, va voluntarily fugitive control history values receiver from the collection size function fit if a reflection is detected say that the quasi-strategy is given.
2-definition. If so So if quasi-strategies are found, optional for the dimensional function equality holds number and if there is a moment, then it is we say that it can be caught in the game.
through
the equation of
let's determine the solution in the initial conditions. The following function
and we will enter the set.
3-definition. If optional so for if found, optional is for
inequality would be appropriate if available, the function is called recurrent (abbreviated recurrent) in the sense of Zubov.
If for all can be chosen independently of all t, then is said to be almost periodic [2].
4-definition. If all at points satisfying equation if there is a recursive function function in the interval it is called recurrent (recurrent for short) in the sense of Zubov.
1-lemma. Let's assume all so for s vectors exist let the relationship be fulfilled and let the functions be recurrent [3]. That's how it is va the following confirmations are appropriate:
1. and all in relationship is fulfilled here ;
2. Each so for moments are found such that
the inequality holds.
Proof. set ends consists of a convex polyhedron with points. From the condition of the lemma originates. – open set. So it is number is optional for attitude is appropriate. of the lemma from the relation 1-it seems that the confirmation is correct.
functions are recursive, then optional so for there is every one so for moments are found such that the inequality holds. The lemma is proved [4]. In the next places va 2.1- we consider that it is chosen according to the conditions of the lemma.
We define the following functions:
This
we enter the designations.
2-lemma. The following conditions must be met:
1. functions recurrent in;
2. ;
3. All so for is vectors exist attitude will be appropriate.
That's how it is the moment is found that for arbitrary control and arbitrary there exists such a number for which the inequality is fulfilled.
Isbot. From the condition of the lemma for arbitrary
the fulfillment of the inequality follows.
[3] according to lemma 1.3.13 in the article, the function λ is continuous in every set , from which
In turn, D is in the set functions are continuous. taking into account the compactness of the set
we generate the inequality. From this
So
The inequality holds for the moment and some number defined by the condition. The lemma is proved.
let it be According to Lemma 2, the inequality holds.
1- Theorem. The following conditions must be met:
1. da functions recursive;
2. There are such vectors that the relation is fulfilled;
3. There are moments for which
relationship is fulfilled.
U xolda o’yinda tutib olish mumkin.
Proof. In arbitrary admissible controls, the solution of problem (5), (6) is based on the Cauchy formula
has a view. Let us assume that - moments satisfy the conditions of the theorem, and - be an arbitrary admissible control of the escaper , where .
This
Let's look at the function. Let us denote the smallest root of this function by It should be noted that according to the 3 condition of the theorem, there is a moment and the inequality holds for at least one i.
Moreover, there exists a number shunday such that for
equality holds. We control the chaser in all as follows:
here larda we think that.
In that case, it is based on the Cauchy formula
according to the determination of, the expression in parentheses above the number becomes zero, so . The theorem is proved.
1-Result. The following conditions must be met:
1. da functions recursive;
2. relation is fulfilled;
In that case, can be caught in the game.
An example. (4) let the system be as follows
here
it is not difficult to show that the function is recurrent.
let it be , here
So the function is recurrent in and, in turn, the function is recurrent.
Confirmation. If it is possible to catch in this game.
References:
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- Чикрий А.А. Конфликтно управляемые процессы. Киев: Наукова думка, 1992. 380с.
- Umrzaqov, Nodirbek (2021) "Sufficient condition for the possibility of completing the pursuit," Scientific Bulletin. Physical and Mathematical Research: Vol. 3 : Iss. 1 , Article 14.